Đúng ghi Đ, sai ghi S vào chỗ chấm:
a) \(\frac{3}{7}+\frac{1}{3}x\frac{3}{7}=\frac{16}{21}x\frac{3}{7}=\frac{16}{49}\) ......
b)\(\frac{5}{9}+\frac{1}{5}x\frac{5}{6}=\frac{5}{9}x\frac{1}{6}=\frac{13}{18}\) ......
c)\(\frac{13}{9}-\frac{7}{9}:\frac{2}{3}=\frac{6}{9}:\frac{3}{2}=1\) ......
d)\(\frac{11}{8}-\frac{5}{8}:\frac{3}{4}=\frac{11}{8}-\frac{5}{8}x\frac{4}{3}=\frac{11}{8}-\frac{10}{24}=\frac{23}{24}\) ......
bài 1 : tính phân số:
a) \(\frac{5}{7}+\frac{4}{9}=?;\frac{4}{5}-\frac{2}{3}=?;\frac{9}{11}+\frac{3}{8}=?;\frac{16}{25}-\frac{2}{5}=?\)=?
b)\(5+\frac{3}{5}=?;10-\frac{9}{16}=?;\frac{2}{3}-\left(\frac{1}{6}+\frac{1}{8}\right)=?\)
c)\(\frac{5}{7}+\frac{7}{6}=?;\frac{7}{12}+\frac{17}{18}=?;\frac{9}{8}+\frac{15}{32}=?;4+\frac{35}{45}=?\)
d)\(\frac{11}{4}-\frac{15}{16}=?;\frac{5}{6}-\frac{5}{8}=?;\frac{196}{64}-2=?;3-\frac{13}{9}=?\)
e)\(\frac{8}{5}+\frac{7}{6}+\frac{5}{9}-2=?;3-\frac{5}{6}-\frac{4}{9}+\frac{32}{24}=?\)
1. Tính nhanh
\(\frac{1}{2}\)x \(\frac{2}{3}\)x \(\frac{3}{4}\)x\(\frac{4}{5}\)x \(\frac{5}{6}\)x\(\frac{6}{7}\)x \(\frac{6}{7}\)x \(\frac{7}{8}\)x\(\frac{8}{9}\text{ }\)x \(\frac{9}{10}\)
\(\frac{1}{2}\): \(\frac{3}{2}\): \(\frac{5}{4}\)\(\frac{6}{5}\):\(\frac{7}{6}\):\(\frac{8}{7}\)
\(\frac{5}{9}x\frac{9}{6}x\frac{7}{3}x\frac{6}{5}x\frac{3}{8}\)=
người nào giải nhanh và đúng nhất tớ sẻ tích
Giúp mình nhé : Tính bằng 2 cách :
\(a,\left(\frac{6}{11}+\frac{5}{11}\right)x\frac{3}{7}\)
\(b,\frac{3}{5}x\frac{7}{9}+\frac{3}{5}x\frac{2}{9}\)
\(\frac{1}{1×2}+\frac{1}{2×3}\: +\frac{1}{3×4}\: +\frac{1}{4×5}+\frac{1}{5×6}\: +\frac{1}{6×7}+\frac{1}{7×8}+\frac{1}{8×9}\: =?\)
tính bằng hai cách
a) \(\left(\frac{6}{11}+\frac{5}{11}\right)x\frac{3}{7}\) b) \(\frac{3}{5}x\frac{7}{9}+\frac{3}{5}x\frac{2}{9}\)
c) \(\left(\frac{6}{7}-\frac{4}{7}\right):\frac{2}{5}\) d) \(\frac{8}{15}:\frac{2}{11}+\frac{7}{15}:\frac{2}{11}\)
giúp mik nha
câu 1 ; 85\(\div\)96 = \(\frac{a}{96}\)
câu 2; x-\(\frac{2}{9}\)= \(\frac{1}{6}\)
câu 3 ; tìm x biết ;\(\frac{1}{6}\)+x =\(\frac{2}{9}\)
Tính:
a)\(\frac{6}{8}\)x\(\frac{7}{6}\)b) \(6\)x\(\frac{7}{9}\)c)\(\frac{4}{6}\):\(\frac{8}{2}\)