Question

\(\frac{6-\sqrt{6}}{\sqrt{6}-1}+\frac{6+\sqrt{6}}{\sqrt{6}}\)

Rút gọn

Answer 1

\(=\frac{\sqrt{6}\left(\sqrt{6}-1\right)}{\sqrt{6}-1}+\frac{\sqrt{6}\left(\sqrt{6}+1\right)}{\sqrt{6}}=\sqrt{6}+\sqrt{6}+1=2\sqrt{6}+1\)

Answer 2

\(\frac{6-\sqrt{6}}{\sqrt{6-1}}\)+  \(\frac{6+\sqrt{6}}{\sqrt{6}}\) =   \(\frac{-\sqrt{30}+6\sqrt{5}}{5}\) +  \(1+\sqrt{6}\) =  \(\frac{\sqrt{6}\left(\sqrt{6-1}\right)}{\sqrt{6-1}}\) +  \(\frac{\sqrt{6}\left(\sqrt{6-1}\right)}{\sqrt{6}}\) = \(\sqrt{6}+\sqrt{6}+1=2\sqrt{6+1}\)