\(=\frac{2^{12}\cdot3^{10}+2^9\cdot3^9\cdot2^3\cdot3\cdot5}{\left(-6\right)^{11}-2^{12}\cdot3^{12}}=\frac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{\left(-6\right)^{11}-6^{12}}=\frac{2^{12}\cdot3^{10}\cdot\left(1+5\right)}{\left(-6\right)^{11}\left(1+6\right)}=\frac{6^{10}\cdot2^2\cdot2\cdot3}{\left(-6\right)^{11}\cdot7}=\frac{6^{11}\cdot4}{\left(-6\right)^{11}\cdot7}=\frac{-4}{7}\)
\(\frac{7.\left(4^6.9^5+6^9.120\right)}{-8^4.3^{12}-6^{11}}\)= bn?
Gía trị biểu thức :\(\frac{7.\left(4^6.9^5+6^9.120\right)}{-8^4.3^{12}-6^{11}}\)
Tính A = \(\frac{7.\left(4^6.9^5+6^9.120\right)}{-8^4.3^{12}-6^{11}}\)
Gía trị của biểu thức : \(\frac{7.\left(4^6.9^5+6^9.120\right)}{-8^4.3^{12}-6^{11}}\)
Giá trị của biểu thức \(\frac{7.\left(4^6.9^5+6^9.120\right)}{-8^4.3^{12}-6^{11}}\)Bằng?
$\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}$
\(^{\left(\frac{5^4-5^3}{125^4}\right)^3}\)
\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(\frac{\left(-0,7\right)^2.\left(-5\right)^3}{\left(-2\frac{1}{3}\right)^3.\left(1\frac{1}{2}\right)^4.\left(-1\right)^5}\)
\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(\frac{4^6.9^5^+6^9.120}{8^4.3^{12}-6^{11}}\)
