Question

\(\frac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)

1.Rút gọn: ( Bài ở trên )

Answer 1

\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}=\frac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}=\frac{-2}{6}=\frac{-1}{3}\)

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Answer 2

\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)=\(\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)=\(\frac{2^{10}.\left(3^8-3^9\right)}{2^{10}.3^8.\left(1+5\right)}\)=\(\frac{-13122}{6561.6}\)=\(-\frac{1}{3}\)