\(=\frac{\left(2^2\right)^{10}+\left(2^3\right)^4}{\left(2^2\right)^5+\left(2^3\right)^6}=\frac{2^{20}+2^{12}}{2^{10}+2^{18}}=\frac{2^{12}\left(2^8+1\right)}{2^{10}\left(2^8+1\right)}=\frac{2^{12}}{2^{10}}=4\)
nhớ tick tui nha pan tui giải kĩ rùi đó
\(=\frac{\left(2^2\right)^{10}+\left(2^3\right)^4}{\left(2^2\right)^5+\left(2^3\right)^6}=\frac{2^{20}+2^{12}}{2^{10}+2^{18}}=\frac{2^{12}\left(2^8+1\right)}{2^{10}\left(2^8+1\right)}=\frac{2^{12}}{2^{10}}=4\)
nhớ tick tui nha pan tui giải kĩ rùi đó
A)\(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}.\frac{4}{10}.\frac{5}{12}....\frac{30}{62}.\frac{31}{64}=4^x\)
B)\(\frac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}.\frac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=8^x\)
tính:
a)\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
b)\(\frac{2^{15}.9^4}{6^3.8^3}\)
c)\(\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
a,\(B=\frac{4^{10}+8^4}{4^5+8^6}\)
b,\(C=\frac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}\)
Cho \(S=\frac{3}{2}+\frac{4}{3}+\frac{5}{4}+\frac{6}{5}+\frac{7}{6}+\frac{8}{7}+\frac{9}{8}+\frac{10}{9}+\frac{11}{10}+\frac{12}{11}\)
So sánh S với 10
a)\(\frac{45^{10}.5^{10}}{75^{10}}\)
b)\(\frac{\left(0,8\right)^5}{\left(0,4\right)^6}\)
c)\(\frac{2^{15}.9^4}{6^3.8^3}\)
d)\(\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
Rút gọn :
\(A=\frac{4^6.9^5+69.120}{8^4.3^{12}+6^{11}}\)
\(B=\frac{10^4+5.10^3+5^4}{25}\)
\(C=\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
a) \(\frac{0,8^5}{0,4^6}\) b)\(\frac{8^{10}+4^{10}}{8^4+4^{11}}\) c)\(\frac{2^{15}\cdot9^4}{6^3\cdot8^3}\)
\(\frac{\frac{3}{8}-\frac{3}{10}+\frac{3}{11}+\frac{3}{12}}{\frac{-5}{6}+\frac{5}{10}+\frac{5}{11}+\frac{5}{12}}+\frac{\frac{3}{2}+1+\frac{3}{4}}{\frac{5}{2}+\frac{5}{3}+\frac{5}{4}}\)
-5/6 là -5/8
Tính nhanh
Tính giá trị biểu thức :
a ,\(\frac{45^{10}.5^{10}}{75^{10}}\)
b,\(\frac{\left(0,8\right)^5}{\left(0,4\right)^6}\)
c,\(\frac{2^{15}.9^4}{6^3.8^3}\)
d\(\frac{8^{10}+4^{10}}{8^4+4^{11}}\)