Question

\(\frac{3^8\cdot2^6+9^4\cdot4^4}{3^9\cdot4^3-3^8\cdot2^8}=?\)

Answer 1

\(\frac{3^8.2^6+3^8.2^8}{3^9.2^6-3^8.2^8}\)

=\(\frac{3^8.2^6.\left(1+2^2\right)}{3^8.2^6\left(3-2^2\right)}\)

=\(\frac{5}{-1}\)

=\(-5\)

Answer 2

\(\frac{3^8.2^6+9^4.4^4}{3^9.4^3-3^8.2^8}=\frac{3^8.2^6+3^8.2^8}{3^9.2^6-3^8.2^8}=\frac{3^8.2^6\left(1+2^2\right)}{3^8.2^6\left(3-2^2\right)}\)

=\(\frac{3^8.2^6.5}{3^8.2^6.\left(-1\right)}=\frac{5}{-1}=\frac{-5}{1}=5\)

Answer 3

xin lỗi mk viết nhầm =-5 chứ ko phải =5