Question

\(\frac{3}{5}+\frac{3}{7}+\frac{3}{11}\)phần\(\frac{7}{5}+1+\frac{7}{11}\)

chia \(\frac{1}{3}-\frac{1}{4}+\frac{1}{5}\)

phần\(\frac{7}{6}-\frac{7}{8}+\frac{7}{10}\)

Answer 1

\(\frac{\frac{3}{5}+\frac{3}{7}+\frac{3}{11}}{\frac{7}{5}+1+\frac{7}{17}}\div\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}\)

\(=\frac{\frac{3}{5}+\frac{3}{7}+\frac{3}{11}}{\frac{7}{5}+\frac{7}{7}+\frac{7}{17}}\div\frac{\frac{2}{6}-\frac{2}{8}+\frac{2}{10}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}\)

\(=\frac{3\left(\frac{1}{5}+\frac{1}{7}+\frac{1}{11}\right)}{7\left(\frac{1}{5}+\frac{1}{7}+\frac{1}{11}\right)}\div\frac{2\left(\frac{1}{6}-\frac{1}{8}+\frac{1}{10}\right)}{7\left(\frac{1}{6}-\frac{1}{8}+\frac{1}{10}\right)}\)

\(=\frac{3}{7}\div\frac{2}{7}\)

\(=\frac{3}{7}\times\frac{7}{2}=\frac{3}{2}\)