30/43=1/43/30=1/1+13/30=1/1+1/30/13=1/1+1/30/13=1/1+1/2+4/13=1/1+1/2+1/13/4=1/1+1/2+1/3+1/4
vậy a=1, b=2, c=3, d=4
\(\frac{30}{43}=\frac{1}{\frac{43}{30}}=\frac{1}{1+\frac{13}{30}}=\frac{1}{1+\frac{1}{\frac{30}{13}}}=\frac{1}{1+\frac{1}{2+\frac{4}{13}}}=\frac{1}{1+\frac{1}{2+\frac{1}{\frac{13}{4}}}}=\)
$\frac{1}{1+\frac{1}{2+\frac{1}{3+\frac{1}{4}}}}$
Vậy a = 1 ; b = 2 ; c = 3 ; d =4
\(\frac{1}{1+\frac{1}{2+\frac{1}{3+\frac{1}{4}}}}\)
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