\(\frac{2x+1}{6}=\frac{24}{2x+1}\)
Theo đề bài ta có:
\(\left(2x+1\right)\left(2x+1\right)=24.6=144\)
\(\Rightarrow\left(2x+1\right)^2=144\)
\(\Rightarrow2x+1=12\)
\(\Rightarrow2x=12-1\)
\(\Rightarrow2x=11\)
\(\Rightarrow x=\frac{11}{2}\)
\(\Rightarrow5,5\)
Vậy x = 5,5
Ta có: \(\frac{2x+1}{6}=\frac{24}{2x+1}\Rightarrow\left(2x+1\right)^2=24\times6=144\)
\(\Rightarrow2x+1=\sqrt{144}=12\)
\(\Rightarrow2x=12-1=11\Rightarrow x=\frac{11}{2}=5,5\)
Ta có : 2x + 1 / 6 = 24 / 2x + 1 => ( 2x + 1 )2 = 24 x 6 = 144
=> 2x + 1 = căn 144 = 12
=> 2x = 12 - 1 = 11 => x = 11/2 = 5,5
