\(\frac{2x-1}{3}=\frac{-27}{1-2x}\)
\(\Rightarrow\left(2x-1\right)\left(1-2x\right)=\left(-27\right).3\)
\(\Rightarrow2x-4x^2-1-2x=-81\)
\(\Rightarrow4x^2-1=-81\)
\(\Rightarrow4x^2=-81+1\)
\(\Rightarrow4x^2=-80\)
Vì \(x^2\ge0\)mà \(4x^2=-80\)
\(\Rightarrow x\in\theta\)
tíc mình nha
Câu 1: Tìm x
1/\(\frac{1+3x}{2}=\frac{7}{3}-\frac{x+1}{6}\)
2,\(\left|\frac{2x+1}{3}\right|=\left|\frac{x-1}{5}\right|\)
3,\(\left(\frac{4}{3}+2x\right)^3=\frac{8}{-27}\)
Tìm x trong các tỉ lệ thức sau:
\(\frac{2x-1}{3}=\frac{7}{27.\left(2x+1\right)}\)
Tìm x:
a)\(2.\left(3x-\frac{1}{2}\right)-2x=\frac{1}{2}\left(2x-3\right)\)
b)\(\left(2x-\frac{3}{5}\right)^2=\frac{4}{25}\)
c)\(\left(3x-1\right)^3=27\)
d)\(5-\left|x\right|=2\)
e)|2x+1|-3=3
f)|3-2x|=5
\(\left(5-x\right)\left(3x-\frac{1}{4}\right)=0\)
\(\left(\frac{-1}{3}\right)^{2x-1}=\frac{-1}{27}\) tìm x
Tìm x,y,z biết rằng: \(\frac{x-1}{5}=\frac{y-2}{3}=\frac{z-1}{4}\) và 2x-3y-2z=-27
1/ Rút gọn
\(A=\frac{4^5.9^4-2.6^9}{2^{10}.3^8-6^8.20}\)
\(B=\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)
2/ Tìm x
\(\frac{7^{x+2}+7^{x+1}+7^x}{57}=\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
a) 3x - 1 = 243
b) (\(\frac{2}{3}\))x + 1 = \(\frac{8}{27}\)
c) 3x + 3x + 2 = 270
d) ( x - \(\frac{5}{2}\)) 2 = 144
e) (2x + 1)3 = \(\frac{125}{27}\)
f) (2x - 1)5 = 243
g) ( x - \(\frac{1}{3}\))2 = (\(\frac{9}{4}\))-1
h) (22 - 1)4 = ( 2x - 1)2
i) (2x + 1)2 + (x + 1)10 = 0
k) \(\frac{x-2}{3}\)= \(\frac{x+3}{2}\)
l) \(\frac{2}{x}\)= \(\frac{x}{50}\)
m) \(\frac{x-3}{4}\)= \(\frac{4}{x+3}\)
\(\frac{21}{x}\)=\(\frac{7}{-4}\)
3(x-3) - ( 2x +2)=0
(4x+3) -(2x-1)=5(x-2)
\(\frac{114}{2x}\)=\(\frac{-8}{12}\)
(0,75-\(\frac{5}{6}\)x)\(^3\)=\(\frac{-27}{64}\)
giúp mk nha
đang cần gấp chìu nộp cho cô òi ( ai nhanh + đúng = 20 ticks
bài 1 tính
4.\(\left(\frac{-1}{2}\right)^3-2.\left(\frac{-1}{2}\right)^2+3.\left(\frac{-1}{2}\right)+1\)1
bài 2 : tìm x
a)\(\frac{37-x}{x+13}=\frac{3}{7}\)
b) | x - \(\frac{1}{2}\)| - \(\sqrt{\frac{1}{9}}=\sqrt{\frac{1}{4}}\)
c) \(2^{3x+2}=4^{x+5}\)
d) \(\frac{3^2.3^8}{27^3}=3^x\)
bài 3: tìm x,y
a)\(\frac{2x}{3y}=-\frac{1}{3}\)và -2x+3y=7
