Question

\(\frac{27\cdot18+27\cdot103-27\cdot102}{15.33+33\cdot12}\)

Answer 1

\(\frac{27.18+27.103-27.102}{15.33+33.12}=\frac{27\left(18+103-102\right)}{33\left(15+12\right)}\)

\(=\frac{27.19}{33.27}=\frac{19}{33}\)

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Answer 2

\(\frac{27.18+27.103-27.102}{15.33+33.12}=\frac{27.\left(18+103-102\right)}{33.\left(15+12\right)}=\frac{27.19}{33.27}=\frac{19}{33}\)

Answer 3

\(\frac{27.18+27.103-27.102}{15.33+33.12}=\frac{27.\left(18+103-102\right)}{33.\left(15+12\right)}\)

\(=\frac{513}{891}=\frac{19}{33}\)