\(\frac{2}{3}x-\frac{3}{4}=\frac{4}{3}-x\)
<=>\(\frac{2}{3}x+x=\frac{4}{3}+\frac{3}{4}\)
<=>\(\frac{5}{3}x=\frac{25}{12}\)
<=>\(x=\frac{5}{4}\)
\(\frac{2}{3}x-\frac{3}{4}=\frac{4}{3}-x\)
\(\frac{2}{3}x+x=\frac{4}{3}+\frac{3}{4}\)
\(\frac{5}{3}x=\frac{25}{12}\)
\(x=\frac{25}{12}:\frac{5}{2}\)
\(x=\frac{5}{6}\)
Vậy \(x=\frac{5}{6}\)
\(\frac{2}{3}x-\frac{3}{4}=\frac{4}{3}-x\)
\(\frac{2}{3}x+x=\frac{4}{3}+\frac{3}{4}\)
\(\frac{5}{3}x=\frac{25}{12}\)
\(x=\frac{5}{4}\)