Question

(\(\frac{2}{3}x\)-1) ×(\(\frac{3}{4}X\)+\(\frac{1}{2}\)) = 0

Giúp mik nhanhh vớiii ạ!!! ༎ຶ‿༎ຶ

Answer 1

\(\left(\frac{2}{3}x-1\right).\left(\frac{3}{4}x+\frac{1}{2}\right)=0\)

\(\Leftrightarrow\hept{\begin{cases}\frac{2}{3}x-1=0\\\frac{3}{4}x+\frac{1}{2}=0\end{cases}\Leftrightarrow\hept{\begin{cases}\frac{2}{3}x=1\\\frac{3}{4}x=\frac{-1}{2}\end{cases}\Leftrightarrow}\hept{\begin{cases}x=\frac{3}{2}\\x=-\frac{2}{3}\end{cases}}}\)

vậy \(x=\frac{3}{2}\)hoặc\(x=-\frac{2}{3}\)

Answer 2

trần quốc tuấn

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Answer 3

\(\left(\frac{2}{3}x-1\right)\left(\frac{3}{4}x+\frac{1}{2}\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}\frac{2}{3}x-1=0\\\frac{3}{4}x+\frac{1}{2}=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}\frac{2}{3}x=1\\\frac{3}{4}x=\frac{-1}{2}\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=\frac{-2}{3}\end{cases}}\)

Vậy ...