Question

 \(\frac{1999}{2004}\)+ \(\frac{2001}{2005}+\frac{5}{2004}+\frac{4}{2005}\)

Answer 1

\(\frac{1999}{2004}+\frac{2001}{2005}+\frac{5}{2004}+\frac{4}{2005}\)

=\(\left(\frac{1999}{2004}+\frac{5}{2004}\right)+\left(\frac{2001}{2005}+\frac{4}{2005}\right)\)

=\(1+1\)

=2

Answer 2

\(\frac{1999}{2004}+\frac{2001}{2005}+\frac{5}{2004}+\frac{4}{2005}\)  = \(\frac{1999}{2004}+\frac{5}{2004}+\frac{2001}{2005}+\frac{4}{2005}\)

                                                                 = \(1+1\)  

                                                                 = \(2\)

Click mik nha !!!!!!!!!!!!!!!!!!!

Answer 3

\(\frac{1999}{2004}+\frac{2001}{2005}+\frac{5}{2004}+\frac{4}{2005}\)

=[ 1999/2004 + 5/2004] + [2001/2005+4/2005]

= 1 + 1 = 2

Answer 4

\(=\left(\frac{1999}{2004}+\frac{5}{2004}\right)+\left(\frac{2001}{2005}+\frac{4}{2005}\right)\)

\(=\frac{1999+5}{2004}+\frac{2001+4}{2005}\)

\(=\frac{2004}{2004}+\frac{2005}{2005}\)

\(=1+1=2\)

Answer 5

\(\frac{1999}{2004}\)+ \(\frac{5}{2004}\)+ \(\frac{2001}{2005}\)+\(\frac{4}{2005}\)

1+1=2