Question

\(\frac{1}{4}+\frac{1}{3}:3x=-5\)

Answer 1

\(\frac{1}{4}+\frac{1}{3}:3x=-5\)

\(\frac{1}{4}+\frac{1}{9}x=-5\)

\(\frac{1}{9}x=\left(-5\right)-\frac{1}{4}\)

\(\frac{1}{9}x=\frac{-21}{4}\)

\(x=\frac{-21}{4}:\frac{1}{9}\)

\(x=\frac{-189}{4}\)

Answer 2

\(\frac{1}{4}+\frac{1}{3}\div3x=-5\)

\(\frac{1}{4}+\frac{1}{9}x=-5\)

\(\frac{1}{9}x=\left(-5\right)-\frac{1}{4}\)

\(x=\frac{-21}{4}\div\frac{1}{9}\)

\(x=\frac{-189}{4}\)