Question

\(\frac{1}{3}\)+ \(\frac{3}{4}\)x \(\frac{5}{9}\)=

\(\frac{7}{12}\)-\(\frac{5}{4}\)x\(\frac{2}{15}\)=

y+\(\frac{1}{4}\)=\(\frac{7}{8}\)-\(\frac{3}{8}\)

y-\(\frac{5}{12}\)=\(\frac{2}{3}\)-\(\frac{1}{4}\)

\(\frac{12}{7}\)x y=\(\frac{16}{21}\)

\(\frac{5}{4}\): y =\(\frac{7}{12}\)

Answer 1

a) \(\frac{27}{36}=\frac{3}{4}\)

b) \(\frac{45}{60}=\frac{3}{4}\)

c) \(\frac{2}{4}=\frac{1}{2}\)

d) \(\frac{10}{12}=\frac{5}{6}\)

e) \(\frac{112}{252}=\frac{4}{9}\)

Đúng nha bạn !!@@

 

Answer 2

\(\frac{1}{3}+\frac{3}{4}x\frac{5}{9}=\frac{1}{3}+\frac{5}{12}=\frac{3}{4}\)

\(\frac{7}{12}-\frac{5}{4}x\frac{2}{15}=\frac{7}{12}-\frac{1}{6}=\frac{5}{12}\)

\(y+\frac{1}{4}=\frac{7}{8}-\frac{3}{8}=y+\frac{1}{4}=\frac{1}{2}=\frac{1}{2}-\frac{1}{4}=\frac{1}{4}\)

\(y-\frac{5}{12}=\frac{2}{3}-\frac{1}{4}=y-\frac{5}{12}=\frac{5}{12}=\frac{5}{12}+\frac{5}{12}=\frac{5}{6}\)

\(\frac{12}{7}xy=\frac{16}{21}=\frac{16}{21}:\frac{12}{7}=\frac{4}{9}\)

\(\frac{5}{4}:y=\frac{7}{12}=\frac{5}{4}:\frac{7}{12}=\frac{15}{7}\)