\(\frac{1}{2}x+150\%x=2014\)
\(\frac{1}{2}x+\frac{3}{2}x=2014\)
\(2x=2014\)
\(x=2014:2\)
\(x=1007\)
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Tìm x biết
\(\left(\frac{1}{2}+\frac{1}{3}+....+\frac{1}{2014}+\frac{1}{2015}\right).x=\frac{2014}{1}+\frac{2013}{2}+\frac{2012}{3}+...+\frac{2}{2013}+\frac{1}{2014}\)
so sanh \(a=\frac{2013}{2014}+\frac{2014}{2015}\) va \(b=\frac{2013+2014}{2014+2015}\)
\(\frac{3}{x+1}
Tìm x: \(\frac{x+4}{2011}+\frac{x+3}{2012}\)=\(\frac{x+2}{2013}+\frac{x+1}{2014}\)
tìm x biết :(\(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2014}.x=\frac{2013}{1}+\frac{2012}{2}+....+\frac{2}{2012}+\frac{1}{2013}\)
tim x
\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}=\frac{2014}{2015}\)
phần a : \(\frac{x+2}{2010}+\frac{x+2}{2011}+\frac{x+2}{2012}=\frac{x+2}{2013}+\frac{x+2}{2014}\)
phần b :\(\frac{x+4}{2000}+\frac{x+3}{2001}=\frac{x+2}{2002}+\frac{x+1}{2003}\)
Tìm x, biết:
\(\frac{x+1}{2013}+\frac{x+2}{2012}=\frac{x+3}{2014}+\frac{x+4}{2010}\)
\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\times\left(x+1\right)}=\frac{2013}{2014}\)
x= mấy
tìm x biết \(1+\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+.....+\frac{2}{x\left(x+1\right)}=1\frac{2014}{2016}\)