\(\frac{1}{2}-\left\{\frac{2}{3}.x-\frac{1}{3}\right\}=\frac{2}{3}\)
\(\frac{2}{3}.x-\frac{1}{3}=\frac{1}{3}-\frac{2}{3}\)
\(\frac{2}{3}.x-\frac{1}{3}=\frac{-1}{3}\)
\(\frac{2}{3}.x=\frac{-1}{3}+\frac{1}{3}\)
\(\frac{2}{3}.x=0\)
\(x=0:\frac{2}{3}\)
\(x=0\)
Vậy \(x=0\)