Question

\(\frac{12-3x}{32}=\frac{6}{4-x}\)

Answer 1

\(\frac{12-3x}{32}=\frac{6}{4-x}\)

\(\Rightarrow\left(12-3x\right)\left(4-x\right)=6\times32\)

\(\Rightarrow3\left(4-x\right)\left(4-x\right)=192\)

\(\Rightarrow3\left(4-x\right)^2=192\)

\(\Rightarrow\left(4-x\right)^2=192\div3\)

\(\Rightarrow\left(4-x\right)^2=64\)

\(\Rightarrow\left(4-x\right)^2=8^2\)

\(\Rightarrow\orbr{\begin{cases}4-x=-8\\4-x=8\end{cases}\Rightarrow\orbr{\begin{cases}x=4+8\\x=4-8\end{cases}\Rightarrow}\orbr{\begin{cases}x=12\\x=-4\end{cases}}}\)

    Vậy \(x=12;x=-4\)