\(\frac{1}{1.2}+\frac{1}{2.3}+..+\frac{1}{99.100}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+..+\frac{1}{99}-\frac{1}{100}=1-\frac{1}{100}=\frac{99}{100}\)
=1/1 - 1/2 +1/2 -1/3+1/3 - 1/4+...+1/99 - 1/100
=1/1 - 1/100
=100/100 - 1/100
=99/100
\(\frac{1}{1.2}+\frac{1}{2.3}+..+\frac{1}{99.100}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+..+\frac{1}{99}-\frac{1}{100}=1-\frac{1}{100}=\frac{99}{100}\)
=1/1 - 1/2 +1/2 -1/3+1/3 - 1/4+...+1/99 - 1/100
=1/1 - 1/100
=100/100 - 1/100
=99/100
\(\frac{1}{1.2}+\frac{1}{2.3}+.....+\frac{1}{99.100}\)
\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{99.100}=?\)
Tính : \(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+......+\frac{1}{99.100}\)
chứng minh:\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}< 1\)
Tính
\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{98.99}+\frac{1}{99.100}\)
\(NGU=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{99.100}\)
Tính NGU?
tính nhanh :\(B=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}\)
\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+.....+\frac{1}{99.100}=??\)
ai làm dc mình k
Tuyển BFF nha, 2k7 !!!
\(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{99.100}\)
NHANH NHÁ CÁC BẠN!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{98.99}+\frac{1}{99.100}\)