\(\frac{10^4.81-16.15^2}{4^4.675}\)
= \(\frac{2^4.5^4.3^4-2^4.3^2.5^2}{4^4.3^3.5^2}\)
= \(\frac{2^4.5^2.3^4-2^4.3^2.5^2}{2^8.3^3.5^2}\)= \(\frac{2^4.5^2.3^2\left(3^2-1\right)}{2^8.3^3.5^2}\)= \(\frac{8}{2^4.3}=\frac{1}{6}\)
mấy bài khó còn làm dc ko lẽ ko làm dc bài này hay quân kiến thức cũ vậy bn
\(\frac{10^4.81-16.15^2}{4^4.675}=\frac{2^4.5^4.3^4-2^4.3^2.5^2}{2^8.3^3.5^2}\)
\(=\frac{2^4.3^2.5^2.\left(5^2.3^2-1\right)}{2^8.3^3.5^2}\)
\(=\frac{25.9-1}{2^4.3}=\frac{225-1}{16.3}=\frac{224}{48}=\frac{14}{3}\)