Tính
\(\frac{1}{2}-\frac{1}{3}-\frac{2}{3}+\frac{1}{4}-\frac{2}{4}+\frac{3}{4}+...+\frac{1}{10}+\frac{2}{10}+...+\frac{9}{10}\)
Tính hợp lí :\(\orbr{\begin{cases}\\\end{cases}9-\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{10}\right):\left(\frac{1}{2}+\frac{2}{3}+\frac{3}{4}+...+\frac{9}{10}\right)}\)
Bài 7:
a) \(\frac{10}{3}.\frac{1}{2}-\left(\frac{1}{2}.x-\frac{1}{3}\right)+\frac{1}{5}\)\(=\frac{3}{5}:\frac{1}{2}\)
b) \(\left[\left(x-\frac{1}{2}\right):6+4\right]\)\(.\frac{2}{3}=\frac{3}{5}.\frac{40}{6}\)
c) \(5\frac{9}{10}:\frac{3}{2}-\left(2\frac{1}{3}.4\frac{1}{2}-2.2\frac{1}{3}\right):\frac{7}{4}\)
Giúp mk vs ạ. mk cảm ơn
Tìm x : a) x + \(\frac{4}{7}=1\)
b) \(\frac{x}{10}=\frac{2}{5}\)
c) \(\frac{5}{9}-\frac{2}{9}nhânx=\frac{1}{3}\)
d)\(\frac{1}{3}nhânx+40\%nhânx=\frac{1}{15}\)
Thực hiện phép tính
a) \(\left(4\frac{1}{9}+3\frac{1}{4}\right).2\frac{1}{4}+2\frac{3}{4}\)
b) \(1+\left(\frac{9}{10}-\frac{4}{5}\right):3\frac{1}{6}\)
c) (-7 + |13|) - (13 - |-7| - 25) - (25 + |-10| - 9 )
Tính
a,\(\frac{2^{10}\cdot55+2^{10}\cdot26}{2^8\cdot27}\)
b,120:{300:[150-(2.53-23.25)]}
c,\(\left[\left(\frac{40}{130}-\frac{12}{13}\right)\cdot40\%+0,15\right]:\frac{-5}{52}\)
d,\(\frac{0,8:\left(\frac{4}{5}\cdot1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{\left(6\frac{5}{9}-3\frac{1}{4}\right)\cdot2\frac{2}{17}}+\left(1,2+0,5\right):\frac{1}{5}\)
Bài 2: (3 đ) Thực hiện phép tính:
a)\(\left[4\frac{1}{9}+3\frac{1}{4}\right].2\frac{1}{4}+2\frac{3}{4}\)
b)\(1+\left[\frac{9}{4}+\frac{4}{5}\right]:3\frac{1}{6}\)
c)(-7+|13|)-(13-|-7|-25)-(25+|-10|-9)
a)\(\frac{7}{x}<\frac{x}{4}<\frac{10}{x}\)
b) Cho A=\(\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+...+\frac{1}{9^2}\). Chứng tỏ: \(\frac{8}{9}>A>\frac{2}{5}\)