= \(\frac{5}{8}.\left(\frac{5}{12}+\frac{7}{12}\right)+2\frac{1}{8}\)
=> \(\frac{5}{8}.1+2\frac{1}{8}\)=> \(\frac{5}{8}+\frac{17}{8}=\frac{22}{8}=\frac{11}{4}\)
#Hk_tốt
#kEn'Z
\(\frac{-5}{8}.\frac{5}{12}+\frac{-5}{8}.\frac{7}{12}+2\frac{1}{8}=\frac{-5}{8}.\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{17}{8}=\frac{-5}{8}.1+\frac{17}{8}=\frac{-5}{8}+\frac{17}{8}=\frac{12}{8}=\frac{3}{4}\)
\(\frac{-5}{8}.\frac{5}{12}+\frac{-5}{8}.\frac{7}{12}+2\frac{1}{8}\)
\(=\frac{-5}{8}.\frac{5}{12}+\frac{-5}{8}.\frac{7}{12}+\frac{17}{8}\)
\(=\frac{-5}{8}.\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{17}{8}\)
\(=\frac{-5}{8}.1+\frac{17}{8}\)
\(=\frac{-5}{8}+\frac{17}{8}\)
\(=\frac{12}{8}=\frac{3}{2}\)
\(\frac{-5}{8}.\frac{5}{12}+\frac{-5}{8}.\frac{7}{12}+2\frac{1}{8} \)
\(=\frac{-5}{8}(\frac{5}{12}+\frac{7}{12})+2\frac{1}{8} \)
\(=\frac{-5}{8}.1+2\frac{1}{8} \)
\(=\frac{-5}{8}+2\frac{1}{8} \)
\(=\frac{-5}{8}+\frac{17}{8} \)
\(=\frac{-5+17}{8} \)
\(=\frac{12}{8} \)
\(=\frac{3}{2} \)
...Hok tốt...
.....#Forever love you#.....
\(\frac{-5}{8}.\frac{5}{12}+\frac{-5}{8}.\frac{7}{12}+2\frac{1}{8}\)
\(=\frac{-5}{8}.\frac{5}{12}+\frac{-5}{8}.\frac{7}{12}+\frac{17}{8}\)
\(=\frac{-5}{8}\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{17}{8}\)
\(=\frac{-5}{8}.1+\frac{17}{8}\)
\(=\frac{-5}{8}+\frac{17}{8}\)
\(=\frac{3}{2}\)
#HỌC TỐT#