cau 1 ,cho m,n thuoc n va p la so nguyen to thoa man p/m-1=m+n/p
CMRp^2=n+2
cau 2,cho a,b,c thoa man a+b+c=0 CMRab+bc+ca be hon hoac bang 0
cau 3,bay gio la 4 gio 10 phut hoi sau it nhat bao lau thi hai kim dong ho nam doi dien nhau tren mot duong thang
cau 4,so 2^100 viet trong he thap phan tao thanh 1 so hoi so do co bao nhieu chu so
cau 5,cho a,b,c la so do 3 canh cua mot tam giac vuong voi c la so do canh huyen CMRa^2n+b^2n be hon hoac bang c^2n (n la so tu nhien lon hon 0 )
THU GON DON THUC SAU VA CHO BIET PHAN HE SO ,PHAN BIEN CUA DON THUC THU DUOC
-AX(xy^3).1/4.(-by)^3 (voi a,b la hang so)
cac ban oi giup minh voi
Cho minh hoi bai nay. Chi can tra loi 1 cau cung duoc! Tick cho ai tra loi som nhat, day du nhat.
1. Cho so huu ti y=2a-1/-3. Voi gia tri nao cua a thi y la so duong, y la so am, khong phai so duong cung phai so am?
2. Cho so huu ti x=a-5/a (a khac 0). Voi gia tri nao cua a thi x la so nguyen?
3. Cho so huu ti x=a-3/2a (a khac 0). Voi gia tri nao cua a thi x la so nguyen?
Qua 5 diem ko co 3 diem nao thang hang hoi : a) Ve dc bao nhiu duong thang phan biet di qua 2 trong 5 diem. b) Ve dc bao nhiu doan thang phan biet nhan 2 trong 5 diem do la cac diem dau mut . c) Ve dc bao nhiu tam giac phan biet nhan 3 trong 5 diem lam dinh . Ai tra loi nhanh va dung m cho 1 like . Anh em tra loi dc cau nao thi tra loi gium minh
Qua 5 diem ko co 3 diem nao thang hang hoi : a) Ve dc bao nhiu duong thang phan biet di qua 2 trong 5 diem. b) Ve dc bao nhiu doan thang phan biet nhan 2 trong 5 diem do la cac diem dau mut . c) Ve dc bao nhiu tam giac phan biet nhan 3 trong 5 diem lam dinh . Ai tra loi nhanh va dung m cho 1 like . Anh em tra loi dc cau nao thi tra loi gium minh
[-x4y]2.[-32xyz].a[a la hang so khac o]
cho don thuc 3(a+1/a)x^4y^2 voi a la hang so ,a khac 0
a)tim a de da thuc luon khong am voi moi x,y
b)tim a de da thuc luon khong duong voi moi x,y
cho a,b,c,d la 4 so khac 0 thoa man b^2 =ac va c^2=bd.Cmr\(\frac{a^3+b^3+c^3}{b^3+c^3+d^3}\)=\(\frac{a}{b}\)
tim phan so m\n khac 0 va so tu nhien k biet rang m/n=m+k\n.k