e.(-3/4)3x-1=256/81
f.172x2-79:983=2-3
e.(-3/4)3x-1=256/81
f.172x2-79:983=2-3
(\(\dfrac{-3}{4}\))3x - 1 = \(\dfrac{256}{81}\)
Có thể chia ra 2 trường hợp
Tìm x biết
a. (2x+1)2 =1
b.(3x-2)2=0
c.(x+3)3=-27
d.5x.(53)2=625
e.(-3/4)3x-1=256/81
f.172x2-79:983=2-3
Giúp mk với nhé! Mk đang cần gấp
(-3/4)^3x+5=(81/256)^-1
Tìm x
(-3/4)3x-1=256/81
tìm x:
\(a,5^x.\left(5^2\right)^3=625\)
\(b,\left(\dfrac{12}{15}\right)^x=\left(\dfrac{5}{4}\right)^{-2}-\left(\dfrac{-3}{5}\right)^4\)
\(c,\left(\dfrac{-3}{4}\right)^{3x-1}=\dfrac{256}{81}\)
\(d,172x^2-7^9:98^3=2^{-3}\)
Tìm x biết
(-3/4)^3x -1= 256/81
(5x+1) ^2 =36/49
(X-2/9)^3= (2/6)^6
(8x -1)^2n+1 = 5^2n +1
(-3/4)3x-2=81/256(1/2)3x-1=1/32 GIÚP MÌNH VỚI