Question

đua vê dang tong 2 binh phuong

x^2 +10x +26 +y^2 +2y 

Answer 1

\(=\left(x^2+10x+25\right)+\left(y^2+2y+1\right)\)

\(=\left(x+5\right)^2+\left(y+1\right)^2\)

Answer 2

x^2 +10x +26 +y^2 +2y=(x^2+10x+25)+(y^2+2y+1)

=(x+5)^2+(y+1)^2

Answer 3

#)Giải :

\(x^2+10x+26+y^2+2y=\left(x^2+10+25\right)+\left(y^2+2y+1\right)=x^2+2.5.x+5^2+y^2+2y+1=\left(x+5\right)^2+\left(y+1\right)^2\)

Answer 4

Làm rõ hơn

\(x^2+10x+26+y^2+2y\)

\(=x^2+10x+25+1+y^2+2y\)

\(=\left(x^2+10x+25\right)+\left(y^2+2y+1\right)\)

\(=\left(x^2+2.5.x+5^2\right)+\left(y^2+2.y.1+1^2\right)\)

\(=\left(x+5\right)^2+\left(y+1\right)^2\)