\(\dfrac{2\sqrt{a}}{3}\le1\)
<=>\(2\sqrt{a}\le3\)
<=>\(\sqrt{a}\le\dfrac{3}{2}\)
<=>\(a\le\dfrac{9}{4}\)
Với a\(\ge0\)
\(\dfrac{2\sqrt{a}}{3}\le1\)<=>\(2\sqrt{a}\le3\)
<=>\(\sqrt{a}\le\dfrac{3}{2}\)
<=>\(a\le\dfrac{9}{4}\)
Kết hợp với ĐKXĐ ta được
\(0\le a\le\dfrac{9}{4}\)
\(\ge0\)
\(BPT\Leftrightarrow\dfrac{2\sqrt{a}}{3}\le\dfrac{3}{3}\Leftrightarrow2\sqrt{a}\le3\Leftrightarrow a\le\dfrac{9}{4}\)