Question

c)(x-1)^2=4

d)x^3+2x^2-x-2=0

e)(3x+2)^2-(2x-1)^2=0

a) 3x^2-2x-8=0

b)2x^3-3x^2+3x+8 =0

g) ( x+2)^2-(2x-1)^2=(3x+1)^2

h)2x^2-3=0

i)2x^2+x+3=0

 

 

Answer 1

c(x-1)^2=4

x^2-2x+1=4

x^2-2x+1-4=0

x^2-2x-3=0

x^2-3x+x-3=0

x(x-3)+(x-3)=0

(x-3)(x+1)=0

\(\Rightarrow\hept{\begin{cases}x-3=0\\x+1=0\end{cases}\Rightarrow\hept{\begin{cases}x=3\\x=-1\end{cases}}}\)

Answer 2

d, x^3+2x^2-x-2=0

x^2(x+2)-(x+2)=0

(x+2)(x^2-1)=0

\(\Rightarrow\hept{\begin{cases}x=-2\\x=+-1\end{cases}}\)

Answer 3

e, (3x+2)^2-(2x-1)^2=0

(3x+2-2x+1)(3x+2+2x-1)=0

(x+3)(5x-1)=0

x+3=0=>x=-3

5x-1=0=>5x=1=>x=1/5

Answer 4

a, 3x^2-2x-8=0

3x^2-6x+4x-8=0

3x(x-2)+4(x-2)=0

(x-2)(3x+4)=0

=>x-2=0=>x=2

=>3x+4=0=>x=-4/3