Question

Cuối cùng: Tìm giá trị của biểu thức sau:

a)\(\frac{4^2\times4^3}{2^{10}}\)

b)\(\frac{\left(0,6\right)^5}{\left(0,2\right)^6}\)

c)\(\frac{2^7\times9^3}{6^5\times8^2}\)

d)\(\frac{6^3+3\times6^2+3^3}{-13}\)

Answer 1

d)\(\frac{6^3+3\cdot6^2+3^3}{-13}=\frac{3^3\cdot2^3+3^3\cdot2^2+3^3}{-13}=\frac{3^3\left(8+4+1\right)}{-13}=\frac{3^3\cdot13}{-13}=-27\)

giang làm a,b,c rồi nên làm d thôi

lười quá, hehe ^_^

Answer 2

a) \(\frac{4^2\cdot4^3}{2^{10}}=\frac{\left(2^2\right)^2.\left(2^2\right)^3}{2^{10}}=\frac{2^4.2^6}{2^{10}}=\frac{2^{10}}{2^{10}}=1\)

b)\(\frac{\left(0,6\right)^5}{\left(0,2\right)^6}=\frac{\left(0,2.3\right)^5}{\left(0,2\right)^6}=\frac{\left(0,2\right)^5.3^5}{\left(0,2\right)^6}=\frac{3^5}{0,2}=\frac{243.5}{1}=1215\)

c)\(\frac{2^7.9^3}{6^5.8^2}=\frac{2^7.\left(3^2\right)^3}{\left(2.3\right)^5.\left(2^3\right)^2}=\frac{2^7.3^6}{2^5.3^5.2^6}=\frac{2^7.3^5}{2^{11}.3^5}=\frac{1}{2^4}=\frac{1}{16}\)