\(16^8-8^{10}+4^{14}\)
\(=2^{32}-2^{30}+2^{28}\)
\(=2^{28}\cdot\left(2^4-2^2+1\right)\)
\(=2^{24}\cdot2^4\cdot13\)
\(=2^{24}\cdot208⋮208\left(đpcm\right)\)
16^8-8^10+4^14
= (2^4)^8-(2^3)^10+(2^2)^14
= 2^32-2^30+2^28
= 2^28(2^4-2^2+1)= 2^18 x 13 = 2^14 x 2^4 x 13 = 2^14 x 208 chia hết cho 208
ta có: 168 - 810 + 414 = (24)8 - (23)10 + (22)14
= 232 - 230 + 228
= 224.(28 - 26 + 24)
= 226.208 chia hết cho 208
=> đ p c m
\(16^8-8^{10}+4^{14}\)
=\(4^{16}-4^{15}+4^{14}\)
=\(4^{12}\left(4^4-4^3+4^2\right)\)
=\(4^{12}.208⋮208\left(ĐPCM\right)\)
