Question

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Answer 1

a) \(\frac{7}{15}+x\cdot\frac{5}{6}=\frac{2}{3}\)

=> \(\frac{7}{15}+x=\frac{2}{3}-\frac{5}{6}=-\frac{1}{6}\)

=> \(x=-\frac{1}{6}-\frac{7}{15}=-\frac{19}{30}\)

b) \(x:\frac{5}{6}-\frac{1}{3}=\frac{7}{12}\)

=> \(x:\frac{5}{6}=\frac{7}{12}+\frac{1}{3}=\frac{11}{12}\)

=> \(x=\frac{11}{12}\cdot\frac{5}{6}=\frac{55}{72}\)

c) \(\frac{11}{15}-x:\frac{1}{2}=\frac{5}{7}\)

=> \(x:\frac{1}{2}=\frac{11}{15}-\frac{5}{7}=\frac{2}{105}\)

=> \(x=\frac{2}{105}\cdot\frac{1}{2}=\frac{1}{105}\)

d) \(x\cdot\frac{3}{7}+\frac{1}{6}=\frac{17}{18}\)

=> \(x\cdot\frac{3}{7}=\frac{17}{18}-\frac{1}{6}=\frac{7}{9}\)

=> \(x=\frac{7}{9}:\frac{3}{7}=\frac{7}{9}\cdot\frac{7}{3}=\frac{49}{27}\)

Answer 2

Bài 1 :

\(a,\frac{7}{15}+x\times\frac{5}{6}=\frac{2}{3}\)

\(x\times\frac{5}{6}=\frac{2}{3}-\frac{7}{15}\)

\(x\times\frac{5}{6}=\frac{1}{5}\)

\(x=\frac{1}{5}:\frac{5}{6}\)

\(x=\frac{6}{25}\)

\(b,x:\frac{5}{6}-\frac{1}{3}=\frac{7}{12}\)

\(x:\frac{5}{6}=\frac{7}{12}+\frac{1}{3}\)

\(x:\frac{5}{6}=\frac{11}{12}\)

\(x=\frac{11}{12}\times\frac{5}{6}\)

\(x=\frac{55}{72}\)

\(c,\frac{11}{15}-x:\frac{1}{2}=\frac{5}{7}\)

\(x:\frac{1}{2}=\frac{11}{15}-\frac{5}{7}\)

\(x:\frac{1}{2}=\frac{2}{105}\)

\(x=\frac{2}{105}\times\frac{1}{2}\)

\(x=\frac{1}{105}\)

\(d,x\times\frac{3}{7}+\frac{1}{6}=\frac{17}{18}\)

\(x\times\frac{3}{7}=\frac{17}{18}-\frac{1}{6}\)

\(x\times\frac{3}{7}=\frac{7}{9}\)

\(x=\frac{7}{9}:\frac{3}{7}\)

\(x=\frac{49}{27}\)

Học tốt

Answer 3

Nhầm câu a)

\(\frac{7}{15}+x\cdot\frac{5}{6}=\frac{2}{3}\)

=> \(x\cdot\frac{5}{6}=\frac{2}{3}-\frac{7}{15}=\frac{1}{5}\)

=> \(x=\frac{1}{5}:\frac{5}{6}=\frac{1}{5}\cdot\frac{6}{5}=\frac{6}{25}\)

Answer 4

\(\frac{7}{15}+x×\frac{5}{6}=\frac{2}{3}=>x×\frac{5}{6}=\frac{2}{3}-\frac{7}{15}=>x×\frac{5}{6}=\frac{1}{5}=>x=\frac{1}{5}:\frac{5}{6}=>x=\frac{6}{25}\)

vậy \(x=\frac{6}{25}\)

\(x:\frac{5}{6}-\frac{1}{3}=\frac{7}{12}=>x:\frac{5}{6}=\frac{7}{12}+\frac{1}{3}=>x:\frac{5}{6}=\frac{11}{12}=>x=\frac{11}{12}×\frac{5}{6}=>x=\frac{55}{72}\)

vậy \(x=\frac{55}{72}\)

\(\frac{11}{15}-x:\frac{1}{2}=\frac{5}{7}=>x:\frac{1}{2}=\frac{11}{15}-\frac{5}{7}=>x:\frac{1}{2}=\frac{2}{105}=>x=\frac{2}{105}×\frac{1}{2}=>x=\frac{4}{105}\)

vậy \(x=\frac{4}{105}\)

\(x×\frac{3}{7}+\frac{1}{6}=\frac{17}{18}=>x×\frac{3}{7}=\frac{17}{18}-\frac{1}{6}=>x×\frac{3}{7}=\frac{7}{9}=>x=\frac{7}{9}:\frac{3}{7}=>x=\frac{49}{27}\)

vậy \(x=\frac{49}{27}\)