Ta có \(\frac{n+2}{n-2}=\frac{m+3}{m-3}\Leftrightarrow1+\frac{4}{n-2}=1+\frac{6}{n-2}\)
\(\Leftrightarrow\frac{4}{n-2}=\frac{6}{m-3}\Leftrightarrow4\left(m-3\right)=6\left(n-2\right)\)
\(\Leftrightarrow4m-12=6n-12\)
\(\Leftrightarrow4m=6n\Leftrightarrow2m=3n\)
\(\Leftrightarrow\frac{n}{2}=\frac{m}{3}\left(đpcm\right)\)
Hok tốt
mơn bạn nhiều
Không có chi^^