Xét hiệu :
H = \(\frac{a^2+b^2}{2}-\left(\frac{a+b}{2}\right)^2=\frac{2.\left(a^2+b^2\right)}{4}-\frac{\left(a+b\right)^2}{4}\)
\(=\frac{2a^2+2b^2-a^2-b^2-2ab}{4}=\frac{\left(a-b\right)^2}{2^2}=\left(\frac{a-b}{2}\right)^2\ge0\)\(\forall\)a,b
Dấu " = " xảy ra khi \(\left(\frac{a-b}{2}\right)^2=0\Leftrightarrow a=b\)
\(\Rightarrow\frac{a^2+b^2}{2}\ge\left(\frac{a+b}{2}\right)^2\)
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