Question

CM:n(n-1)(n+3) chia hết cho n²-n

Answer 1

\(n^2-n=n\left(n-1\right)\)

Mà  \(n\left(n-1\right)\left(n+3\right)⋮n\left(n-1\right)\)

\(\Rightarrow n\left(n-1\right)\left(n+3\right)⋮n^2-n\)

Answer 2

n²-n=n(n-1)

n(n-1)(n+3) luôn chia hết cho n(n-1)

Nên n(n-1)(n+3) chia hết cho n²-n