Các câu hỏi tương tự
\(CM:\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{63}>2\)
\(CM,\frac{1}{2}+\frac{1}{3}+...+\frac{1}{63}>2\)
\(CM:\frac{1}{2}+\frac{1}{3}+...+\frac{1}{63}>2\)
B=\(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{63}< 6\)
C=\(1+\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+...+\frac{1}{100^2}< 2\)
Afrac{1}{2}+frac{1}{3}+frac{1}{4}+...+frac{1}{63}2 C1+frac{1}{2}+frac{1}{3}+frac{1}{4}+...+frac{1}{63} 6B1+frac{1}{2^2}+frac{1}{3^2}+frac{1}{4^2}+...+frac{1}{100^2} 2 Dfrac{1}{2}.frac{3}{4}.frac{5}{6}....frac{9999}{10000} frac{1}{100}Mọi người giúp mik nhé, mik đang ôn thi nên cần gấp!
Đọc tiếp
\(A=\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{63}>2\) \(C=1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{63}< 6\)
\(B=1+\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+...+\frac{1}{100^2}< 2\) \(D=\frac{1}{2}.\frac{3}{4}.\frac{5}{6}....\frac{9999}{10000}< \frac{1}{100}\)
Mọi người giúp mik nhé, mik đang ôn thi nên cần gấp!
chứng minh:
B=\(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{63}< 6\)
C=\(1+\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+...+\frac{1}{100^2}< 2\)
1 tháng 5 2018 lúc 19:37
Chứng minh rằng:
a) \(A=1+\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+.........+\frac{1}{100^2}< 2\)
b) \(B=1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+.........+\frac{1}{63}< 6\)
a) \(A=1+\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+...+\frac{1}{2014^2}< 2^{ }\)
b)\(B=1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{63}< 6\)
c)\(C=\frac{1}{2}.\frac{3}{4}.\frac{5}{6}.....\frac{9999}{10000}< \frac{1}{100}\)
Bài 1 : Chứng minh
a) \(A=1+\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+...+\frac{1}{100^2}< 2\)
b) \(B=1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{63}< 6\)
c) \(C=\frac{1}{2}.\frac{3}{4}.\frac{5}{6}.\frac{7}{8}...\frac{9999}{10000}< \frac{1}{100}\)