\(^{c,\left(2^2\right)^{\left(2^2\right)}}\)
\(d,\frac{8^{14}}{4^{12}}\)
\(e,\frac{\left(-\frac{5}{7}\right)^{n+1}}{\left(-\frac{5}{7}\right)^n}\)với 0 lớn hơn hoặc bằng 1
\(g,\left(-\frac{1}{3}\right)^7.3^7\)
\(h,\left(0,125\right)^3.512\)
\(k,\frac{40^{10}.5^{10}}{75^{10}}\)
\(m,\frac{8^{10+4^{10}}}{8^4+4^{11}}\)
a)\(\left(0,25\right)^3.32\) c)\(\frac{8^2.4^5}{2^{20}}\)
b)\(\left(0,125\right)^3.80^4\) d)\(\frac{81^{11}.3^{17}}{27^{10}.9^{15}}\)
mik cần gấp
ai giả đc tặng 3 tick
Tính nhanh:
a) 7,5 . \(\left(\frac{-2}{5}\right).\left(-2,5\right)\)
b) ( - 50,5 ) . 8 . ( - 0,25 )
c) ( 0,125 ) . ( -3,7) . ( -2 )3
Tính hợp lý
a) \(\left(0,25\right)^2.32\) b) \(\left(-0,125\right)^3.80^4\) c)\(\frac{8^2.4^5}{2^{20}}\)
So sánh:
a)\(\left(0,5\right)^6\)và \(\left(0,5\right)^9\)
b)\(\left(-0,125\right)^8\)và \(\left(0,5\right)^{24}\)
c)\(8^{12}\) và \(12^8\)
1, a) \(\left(\frac{1}{4}\right)^{20}.\left(\frac{1}{2}\right)^5\) b) \(\left(\frac{1}{9}\right)^{25}:\left(\frac{1}{3}\right)^{20}\) c) \(\left(\frac{1}{16}\right)^2:\left(\frac{1}{8}\right)^3\)
2, A=\(\frac{10^2-8^2}{6^2}\) b) B=\(\frac{25^4+10^4}{25^2+16}\) c) C=\(\frac{9^2.15^3}{3^7.5^2}\) d) D=\(\frac{6^{10}-3^{10}}{2^{10}-1}\)
Cho \(P\left(x\right)=x^4+ax^3+bx^2+cx+d\), trong đó a, b, c, d là hằng số.
Gia su \(P\left(1\right)=10,P\left(2\right)=20,P\left(3\right)=30\). Hãy tính \(\frac{P\left(12\right)+P\left(-8\right)}{10}\)
So sánh:
a) \(3^6\)và\(6^3\)
b) \(\left(0,5\right)^6\)và \(\left(0,5\right)9\)
c)\(\left(-0,125\right)^8\)và \(\left(0,5\right)^{24}\)
d)\(8^{12}\)và \(12^8\)
TÌM x BIẾT:
a,\(\frac{3}{\left(x+2\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\)
với x\(\notin\){-2;-5;-10;-17}
b,\(\frac{2}{\left(x-1\right)\left(x-3\right)}+\frac{5}{\left(x-3\right)\left(x-8\right)}+\frac{12}{\left(x-8\right)\left(x-20\right)}-\frac{1}{x-20}=\frac{-3}{4}\)
với x\(\notin\){1;3;8;20}
c, TÌM X BIẾT:
\(\frac{x-1}{2009}+\frac{x-2}{2008}=\frac{x-3}{2007}+\frac{x-4}{2006}\)
GIÚP MÌNH CHÚT NHA MÌNH CẦN NGAY. THANKS!