a ) = \(\frac{19}{2}=>9\frac{1}{2}\)
b)= \(\frac{19}{2}=>9\frac{1}{2}\)
c ) = 23\(\frac{8}{9}\)
d) = \(5\frac{3}{7}\)(Cứ v nhân mẫu r cộng tử và giữ nguyên mẫu ví dụ : câu d : 5.7 + 3 =38\(\frac{38}{7}\) )
e ) ....
57/6=9 1/2
95/10 =9 1/2
215/9 =23 8/9
38/7=5 3/7
123/12 =10 1/4
51/10=5 1/10
Please hãy k
Nao Tomori
\(a,\frac{57}{6}=5\frac{27}{6}\)
\(b,\frac{95}{10}=9\frac{5}{10}\)
\(c,\frac{215}{9}=5\frac{170}{9}\)
\(d,\frac{38}{7}=5\frac{3}{7}\)
\(e,\frac{123}{12}=10\frac{3}{12}\)
\(g,\frac{51}{10}=5\frac{1}{10}\)
P/s: Ko chắc đâu nha
\(a,\frac{57}{6}=9\frac{1}{2}\)
\(b,\frac{95}{10}=9\frac{1}{2}\)
\(c,\frac{215}{9}=23\frac{8}{9}\)
\(d,\frac{38}{7}=5\frac{3}{7}\)
\(e,\frac{123}{12}=10\frac{1}{4}\)
\(g,\frac{51}{10}=5\frac{1}{10}\)