Có : \(\frac{n+5}{n+6}=\frac{n+6-1}{n+6}=\frac{n+6}{n+6}-\frac{1}{n+6}=1-\frac{1}{n+6}\)
Để \(\frac{n+5}{n+6}\in Z\Rightarrow n+6\inƯ\left(1\right)\)
\(Ư\left(1\right)\in\left\{\pm1\right\}\Rightarrow n+6\in\left\{1;-1\right\}\)
\(\Rightarrow n\in\left\{-5;-7\right\}\)