Ta có
\(\frac{1}{101}>\frac{2}{3}\)
\(\frac{1}{102}>\frac{2}{3}\)
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\(\frac{1}{300}>\frac{2}{3}\)
Vậy \(\frac{1}{101}+\frac{1}{102}+...+\frac{1}{299}+\frac{1}{300}>\frac{2}{3}\)
Chứng tỏ rằng\(\frac{1}{101}+\frac{1}{102}+...+\frac{1}{299}+\frac{1}{300}>\frac{2}{3}\)
Chứng tỏ rằng \(\frac{1}{101}+\frac{1}{102}+...+\frac{1}{299}+\frac{1}{300}>\frac{2}{3}\)
Chứng tỏ rằng
\(\frac{1}{101}+\frac{1}{102}+...+\frac{1}{299}+\frac{1}{300}\)>\(\frac{2}{3}\)
Chứng tỏ rằng: \(E=\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+...+\frac{1}{299}+\frac{1}{300}< \frac{2}{3}\)
\(F=\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+...+\frac{1}{17}< 2\)
Chứng minh rằng
\(\frac{1}{101}+\frac{1}{102}+.........+\frac{1}{299}+\frac{1}{300}\) > \(\frac{2}{3}\)
Chứng tỏ rằng : \(\frac{1}{101}\) + \(\frac{1}{102}\) +....+\(\frac{1}{299}\)+\(\frac{1}{300}\) > \(\frac{2}{3}\)
CMR:
\(\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+...+\frac{1}{299}+\frac{1}{300}>\frac{2}{3}\)\(\frac{2}{3}\)
CMR
\(\frac{1}{101}+\frac{1}{102}+...+\frac{1}{299}+\frac{1}{300}>\frac{2}{3}\)
\(\frac{1}{1\cdot300}+\frac{1}{2\cdot301}+\frac{1}{3\cdot302}+...+\frac{1}{299\cdot400}\)chứng minh rằng \(\frac{1}{299}\left(\left(1+\frac{1}{2}+...+\frac{1}{101}\right)-\left(\frac{1}{300}+\frac{1}{301}+...+\frac{1}{400}\right)\right)\)=\(\frac{1}{1\cdot300}+\frac{1}{2\cdot301}+\frac{1}{3\cdot302}+...+\frac{1}{299\cdot400}\)
