Chứng tỏ rằng: 1-1/2+1/3-1/4+...+1/99-1/200=1/101+1/102+...+1/199+1/200
chứng tỏ rằng 1-1/2+1/3-1/4+.....+1/99-1/200=1/101+1/102+...+1/199+1/200
Chứng tỏ rằng : \(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{200}=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{199}+\frac{1}{200}\)
Chứng tỏ rằng: \(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{200}=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{199}+\frac{1}{200}\)
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Chứng tỏ: 1-1/2+1/3-1/4+...+1/99-1/100=1/101+1/102+1/199+1/200
Chứng tỏ rằng: \(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{199}+\frac{1}{200}\)
A=1/100^2+1/101^2+1/102^2+…+1/200^2 chứng minh rằng 1/200<A<1/99
Chứng minh rằng 1/200<A<1/99 biết A=1/100^2+1/101^2+1/102^2+…+1/200^2
chứng tỏ rằng 1-\(\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{199}-\frac{1}{200}=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{199}+\frac{1}{200}\)