Question

Chứng tỏ A chia hết cho 6 với A= 2+2^2+2^3+2^4+.....+2^100

giúp mik nha, mik sẽ tick

 

 

Answer 1

A=2+2^2+2^3+2^4+...+2^100

  =(2+2^2)+(2^3+2^4)+(2^5+2^6)+...+(2^99+2^100)

  =6+(2^2.2+2^2.2^2)+(2^4.2+2^4.2^2)+...+(2^98.2+2^98.2^2)

  =6+2^2.(2+2^2)+2^4(2+2^2)+...+2^98.(2+2^2)

  =6.1.2^2.6+2^4.6+...+2^98.6

  =6.(2^2+2^4+...+2^98)

Vì \(6⋮6\)

\(\Rightarrow\)\(6.\left(2^2+2^4+...+2^{98}\right)⋮6\)

     Hay \(A⋮6\)