Question

Chứng minh rằng:

\(\frac{5x^3+5x}{x^4-1}=\frac{5x}{x^3-1}\)

Answer 1

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Answer 2

chắc chắn bn sai đề vp = 5x/ x² -1 thì mới c/m dc

Answer 3

Bạn Đặng Quỳnh Ngân nói đúng

\(\frac{5x^3+5x}{x^4-1}=\frac{5x\left(x^2+1\right)}{\left(x^2\right)^2-1}=\frac{5x\left(x^2+1\right)}{\left(x^2-1\right)\left(x^2+1\right)}=\frac{5x}{x^2-1}\)