B< 1+(1/1.2+1/2.3+...+1/62.63)
B<1+(1-1/2+1/2-1/3+...+1/62-1/63)
B<1+1-1/63
B<2-1/63
B<6-3/189
mà 6-3/189<6
Vậy B<6
b, gọi D=2/3.4/5....10000/10001
Ta có: 1/2<2/3 3/4<4/5 .. ..... 9999/10000<10000/10001
=> C<D 1
C.D=1/2.3.4.....9999/10000.2/3.4/5...10000/10001
C.D=1/10001 2
Từ 1 : C<D => C.C<C.D<1/10001
=>C^2<1/10001<1/10000
=>C^2<(1/100)^2
Vậy C<1/100 (đpcm)
Chứng minh rằng :
a)B=1+1/2+1/3+....+1/63<6
b)C=1/2.3/4.5/6......9999/10000<1/100
Cảm ơn các bạn nha
Chứng minh rằng:
a) A=1+1/2^2+1/3^2+1/4^2+...+1/100^2 bé hơn 2
b) B=1+1/2+1/3+1/4+...+1/63 bé hơn 6
c)M=1/3+1/31+1/35+1/37+ 1/47+1/53+1/61 bé hơn 1/2
d)C=1/2.3/4.5/6....9999/10000 bé hơn 1/100
chứng minh rằng: C=1/2.3/4.5/6....9999/10000<1/100
Chứng tỏ
a, 1/2-1/4+1/8-1/16+1/32-1/64<1/3
b, 1/3-2/3^2+3/3^3-4/3^4+...+99/3^99-100/3^100<3/16
c, 1/2.3/4.5/6...9999/10000<1/100
Bài 1:
a) Cho A=1+1/2+1/3+...+1/127. Chứng minh rằng : A<7
b) Cho B=1/2.3/4.5/6...9999/10000. Chứng minh rằng: B<1/100
Mk cần gấp trg hôm nay. Giúp mk với, thanks
1/2.3/4.5/6.....9999/10000<1/100
So sánh 1/2.3/4.5/6.................9999/10000 vs 1/100
Cho A=1/2.3/4.5/6.....9999/10000.hãy so sánh A và 1/100
Bài 1: Tìm x, biết:
\(\frac{1}{2.3}x+\frac{1}{3.4}x+\frac{1}{4.5}x+.....+\frac{1}{49.50}x=1\)
Bài 2: Chứng minh rằng:
\(a)A=1+\frac{1}{2^2}+\frac{1}{3^2}+\frac{1}{4^2}+.....+\frac{1}{100^2}< 2\)
\(b)B=1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+.....+\frac{1}{63}< 6\)
\(c)C=\frac{1}{2}.\frac{3}{4}.\frac{5}{6}.......\frac{9999}{10000}< \frac{1}{100}\)
Bài 3: Tính tổng:
\(S=\frac{1+2+2^2+2^3+.....+2^{2008}}{1-2^{2009}}\)
