a,=7^4(7^2+7-1)
=7^4.55 vậy nó chia hết cho 55
b,16^5=2^20
2^15(2^5+1)
2^15.33 chia hết cho 33
các câu c,d cũng tương tự
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b) \(16^5+2^{15}⋮33\)
\(=\left(2^4\right)^5+2^{15}\)
\(=2^{20}+2^{15}\)
\(=2^{15}.\left(1+2^5\right)\)
\(=2^{15}.33⋮33\)