-->B=(3^3+3^4)+(3^5+3^6)+...+(3^15+3^16)
-->B=3^3(1+3)+3^5(1+3)+....+3^15(1+3)
-->B=4(3^3+3^5+..+3^15)
-->B chia hết cho 4(ddpcm)
B=33+34+35+...+316
= 33.(1+3)+35.(1+3)+...+315.(1+3)
= 33.4+35.4+...+315.4
= 4.(33+35+...+315)
=> tổng trên chia hết cho 4
=> B chia hết cho 4