Các câu hỏi tương tự
Chung minh rang: \(\frac{1}{3}-\frac{2}{3^2}+\frac{3}{3^3}-\frac{4}{3^4}+....+\frac{99}{3^{99}}-\frac{100}{3^{100}}<\frac{3}{16}\)
chumg minh rang 1/3-2/3^2+3/3^3-4/3^4+...+99/3^99-100/3^100<3/16
chung minh 1/3-2/3^2+3/3^3-4/3^4+...+99/3^99-100/3^100<3/16
cho n=1/3-2/3^2+3/3^3-4/3^4+...+99/3^99-100/3^100 . Chung minh n < 3/16
2, chung minh rang
a, \(\frac{1}{2}-\frac{1}{4}+\frac{1}{8}-\frac{1}{16}+\frac{1}{32}-\frac{1}{64}<\frac{1}{3}\)
b,\(\frac{1}{3}-\frac{2}{^{3^2}}+\frac{3}{3^4}+........+\frac{99}{3^{99}}-\frac{100}{3^{100}}<\frac{3}{16}\)
chung minh rang : 1 / 2 ^ 2 + 1 / 3 ^ 2 + 1 / 4 ^ 2 + . . . + 1 / 100 ^ 2 < 99 / 100
chứng minh: 1/3-2/3^2+3/3^3-4/3^4+...+99/3^99-100/3^100<3/16
Chứng minh rằng : 1/3-2/3^2+3/3^3-4/3^4+...+99/3^99-100/3^100<3/16
chung minh rang A=\(\frac{1}{2}-\frac{2}{2^2}+\frac{3}{2^3}-\frac{4}{2^4}+...+\frac{99}{2^{99}}-\frac{100}{2^{100}}<\frac{2}{9}\)