Chứng minh rằng :100- ( 1+1/2+1/3+...+1/100)=1/2+2/3+3/4+...+99/100
chứng minh rằng:
\(\dfrac{1}{3}+\dfrac{2}{3^2}+\dfrac{3}{3^3}+...+\dfrac{100}{3^{100}}< \dfrac{3}{4}\)
Chứng minh rằng:
C= 1/3+2/32+3/33+4/34+.....+100/3100
Chứng tỏ C<3/4
Chứng minh rằng :
1/3+2/32+3/33+4/34+...+100/3100 <3/4
Chứng minh rằng \(\frac{1}{3}+\frac{2}{3^2}+\frac{3}{3^3}+\frac{4}{4^3}+...+\frac{100}{3^{100}}< \frac{3}{4}\)
- Chứng minh rằng: M = 1/3 + 2/32 + 3/33 + ... + 100/3100 < 3/4
- Chứng minh rằng: M = 1/3 + 2/32 + 3/33 + ... + 100/3100 < 3/4
chứng minh rằng\(D=\frac{1}{3}+\frac{2}{3^2}+\frac{3}{3^3}+\frac{4}{^{3^4}}+...+\frac{100}{3^{100}}<1\)
Chứng minh rằng:
\(\frac{1}{3}+\frac{2}{^{3^2}}+\frac{3}{3^3}+\frac{4}{3^4}+...+\frac{100}{3^{100}}