Các câu hỏi tương tự
Chứng minh 1*3*5*...*99=51/2*52/2*53/2*...*100/2
Chứng minh : 51/2 x 52/2 x 53/2 x.......x 100/2 = 1 x 3 x 5 x 7 x.......x 99
Chứng minh rằng :
\(\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{99}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{100}\right)=\frac{1}{51}+\frac{1}{52}+\frac{1}{53}+\frac{1}{54}+...+\frac{1}{100}\)
Chứng minh rằng 1×3×5×...×99=51/2×52/2×...×100/2
1-1/2+1/3-1/4+1/5-1/6+.....+1/99-1/100=1/51+1/52+1/53+1/54+..+1/100
Chứng minh rằng :
a,1- 1/2 + 1/3 - 1/4 + 1/5 - 1/6 + ...... + 1/ 99 - 1/ 100 = 1 / 51 + 1/ 52 + 1/ 53 + ... + 1/ 100
b, A= 1/3 - 2/ 32 + 3/ 33 - 4/ 34 + .... + 99/ 399 - 100/ 3100 < 3/ 16
chứng minh rằng
51\2*52\1*...*100\2=1*3*5..*99
Chứng minh :(1+1/3+1/5+...+1/99)-(1/2+1/4+1/6+...+1/100)=1/51+1/52+1/53+...+1/100
Chứng minh: 1- 1\2 + 1\3 - 1\4 + 1 \5 - 1\6 + ....... + 1\99 -1\100 = 1\51 + 1\52 + 1\53 + ..........+1\100