\(\frac{202}{1.3}+\frac{202}{3.5}+\frac{202}{5.7}+...+\frac{202}{99.101}\)
\(=202\left(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{99.101}\right)\)
\(=202.\frac{1}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{99}-\frac{1}{101}\right)\)
\(=101\left(1-\frac{1}{101}\right)\)
\(=101.\frac{100}{101}\)
\(=100=10^2\Rightarrowđpcm\)