Ta có : A = 1/3 - 2/3^2 + 3/3^3 - 4/3^4 +...- 2014/3^2014
=> 3A = 1 - 2/3 + 3/3^2 - 4/3^3 +...- 2014/3^2013
=> 4A = 1- 1/3 + 1/3^2 -...- 1/3^2013 - 2014/3^2014
Xét B = 1-1/3+1/3^2 -...- 1/3^2013
=> 3B = 3 - 1 + 1/3 -...- 1/3^2012
=> 4B = 3- 1/3^2013
=> B = (3- 1/3^2013)/4 < 3/4
=> 4A < 3/4 - 2014/3^2014< 3/4
=> A < 3/16 < 3/15 =1/5
Vậy A < 1/5 (đpcm)
Chúc bạn học tốt
Chứng minh: \(\frac{1}{3}-\frac{2}{3^2}+\frac{3}{3^3}-\frac{4}{3^4}+...-\frac{2014}{3^{2014}}<\frac{1}{5}\)
Chứng minh:
\(\frac{1}{3}-\frac{2}{3^2}+\frac{3}{3^3}-\frac{4}{3^4}+...-\frac{2014}{3^{2014}}<\frac{1}{5}\)
Chứng minh: \(\frac{1}{3}-\frac{2}{3^2}+\frac{3}{3^2}-\frac{4}{3^4}+\)\(...-\frac{2014}{3^{2014}}<\frac{1}{5}\).
Chứng minh:
\(\frac{1}{3}-\frac{2}{3^2}+\frac{3}{3^3}-...-\frac{2014}{3^{2014}}< \frac{1}{5}\)
Cho tổng gồm 2014 số hạng, \(S=\frac{1}{4}+\frac{2}{4^2}+\frac{3}{4^3}+\frac{4}{4^4}+...+\frac{2014}{4^{2014}}\). Chứng minh rằng \(S< \frac{1}{2}\).
Chứng minh : \(\frac{1}{2^3}+\frac{1}{3^3}+\frac{1}{4^3}+...+\frac{1}{2014^3}< \frac{1}{4}\).
cho S=\(\frac{1}{4^1}+\frac{2}{4^2}+\frac{3}{4^3}+...+\frac{2014}{4^{2014}}\)
chứng minh S<\(\frac{1}{2}\)
\(s=\frac{1}{4}+\frac{2}{4^2}+\frac{3}{4^3}+........+\frac{2014}{4^{2014}}.\)
CHỨNG MINH RẰNG : S < \(\frac{1}{2}\)
Chứng minh:
\(\frac{1}{3}-\frac{2}{3^2}-\frac{3}{3^3}-...-\frac{2014}{3^{2014}}<\frac{1}{5}\)
